FreeBSD Bugzilla – Attachment 16711 Details for
Bug 30540
[PATCH] spelling and grammar fixes in a comment
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[patch]
file.diff
file.diff (text/plain), 2.00 KB, created by
Tony Finch
on 2001-09-13 00:50:01 UTC
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Description:
file.diff
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Creator:
Tony Finch
Created:
2001-09-13 00:50:01 UTC
Size:
2.00 KB
patch
obsolete
>Index: sys/dev/kbd//atkbdc.c >=================================================================== >RCS file: /home/ncvs/src/sys/dev/kbd/atkbdc.c,v >retrieving revision 1.5.2.1 >diff -u -r1.5.2.1 atkbdc.c >--- sys/dev/kbd//atkbdc.c 2000/03/31 12:51:56 1.5.2.1 >+++ sys/dev/kbd//atkbdc.c 2001/07/26 00:45:45 >@@ -217,10 +217,10 @@ > * I/O access to the controller/keyboard/mouse. The convention requires > * close cooperation of the calling device driver. > * >- * The device driver which utilizes the `kbdio' module are assumed to >+ * The device drivers which utilize the `kbdio' module are assumed to > * have the following set of routines. > * a. An interrupt handler (the bottom half of the driver). >- * b. Timeout routines which may briefly polls the keyboard controller. >+ * b. Timeout routines which may briefly poll the keyboard controller. > * c. Routines outside interrupt context (the top half of the driver). > * They should follow the rules below: > * 1. The interrupt handler may assume that it always has full access >@@ -239,12 +239,12 @@ > * Therefore, `spltty()' must be strategically placed in the device > * driver code. Also note that the timeout routine may interrupt > * `kbdc_lock()' called by the top half of the driver, but this >- * interruption is OK so long as the timeout routine observes the >- * the rule 4 below. >+ * interruption is OK so long as the timeout routine observes >+ * rule 4 below. > * 4. The interrupt and timeout routines should not extend I/O operation >- * across more than one interrupt or timeout; they must complete >- * necessary I/O operation within one invokation of the routine. >- * This measns that if the timeout routine acquires the lock flag, >+ * across more than one interrupt or timeout; they must complete any >+ * necessary I/O operation within one invocation of the routine. >+ * This means that if the timeout routine acquires the lock flag, > * it must reset the flag to FALSE before it returns. > */
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bug 30540
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